The VBA INSTR function is listed under the text category of VBA functions. When you use it in a VBA code, it returns the starting position number of a sub-string (specified by you) from another string. In simple words, it works like the FIND and SEARCH (worksheet functions).
InStr([Start], String1, String2, [Compare])
- [Start]: An integer to specify the position from where you want to start the search [This is an optional argument and if omitted VBA takes 1 by default].
- String1: The string in which you want to search.
- String2: The string that you want to search for.
- [Compare]: A string value to define the comparison to make while filtering array [This is an optional argument and if omitted VBA takes vbBinaryCompare by default].
- vbBinaryCompare: For binary comparison.
- vbTextCompare: For text comparison.
- vbDatabaseCompare: For Database Comparison.
To practically understand how to use VBA INSTR function, you need to go through the below example where we have written a vba code by using it:
Sub example_INSTR() Range("B1").Value = InStr(Range("A1"), " ") End Sub
In the above code, we have used the INSTR to find the space within the value (Mick Griffin) in cell A1 and it has returned 5 as a result, there’s the first space is between “Mick” and “Griffin” whose position is 5.
Below are some important points which you need to take care of while using INSTR function in VBA.
- If “string1” cannot be found in “string2” then it will 0 is the result.